8a+a^2=2a+7

Solution for 8a+a^2=2a+7 equation:

8a+a^2=2a+7

We move all terms to the left:

8a+a^2-(2a+7)=0

We get rid of parentheses

a^2+8a-2a-7=0

We add all the numbers together, and all the variables

a^2+6a-7=0

a = 1; b = 6; c = -7;
Δ = b2-4ac
Δ = 62-4·1·(-7)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-8}{2*1}=\frac{-14}{2}
=-7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+8}{2*1}=\frac{2}{2}
=1
$